如何获取树状自定义对象的大小

class TreeNode:
    def __init__(self, value, children=None):
        self.value = value
        self.children = children or []

def get_tree_size(node):
    if not node.children:
        # 叶子节点的大小为节点值的大小
        return get_object_size(node.value)
    
    size = get_object_size(node.value)
    for child in node.children:
        size += get_tree_size(child)
    
    return size

def get_object_size(obj):
    # 计算对象的大小，具体实现根据对象类型而定
    # 返回对象的大小，单位可以是字节或其他合途径的度量单位
    pass

# 示例用法
root = TreeNode("Root", [
    TreeNode("Child 1", [
        TreeNode("Grandchild 1"),
        TreeNode("Grandchild 2")
    ]),
    TreeNode("Child 2")
])

tree_size = get_tree_size(root)
print("树状对象的大小为：", tree_size)