如何获取listview项的ID，而不是列表视图上的位置？

// 自定义适配器
public class MyAdapter extends ArrayAdapter<String> {
    private List<String> itemList;
    private List<Integer> itemIdList;

    public MyAdapter(Context context, int resource, List<String> items, List<Integer> itemIds) {
        super(context, resource, items);
        itemList = items;
        itemIdList = itemIds;
    }

    @Override
    public View getView(int position, View convertView, ViewGroup parent) {
        View view = super.getView(position, convertView, parent);
        view.setTag(itemIdList.get(position)); // 将标识符与项关联起来
        return view;
    }
}

// 在使用ListView的地方
ListView listView = findViewById(R.id.listView);
List<String> items = new ArrayList<>();
List<Integer> itemIds = new ArrayList<>();

// 填充数据源
items.add("Item 1");
items.add("Item 2");
items.add("Item 3");

// 为每个项生成唯一的ID
itemIds.add(1);
itemIds.add(2);
itemIds.add(3);

// 创建适配器并设置给ListView
MyAdapter adapter = new MyAdapter(this, android.R.layout.simple_list_item_1, items, itemIds);
listView.setAdapter(adapter);

// 获取ListView项的ID
listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        int itemId = (int) view.getTag(); // 获取与项关联的标识符
        // 使用项的ID进行后续操作
        // ...
    }
});