如何获得与打开HANDLE相关联的名称

#include<iostream>
#include<Windows.h>
#include <FileAPI.h>

int main() {
    // 打开一个文件句柄
    HANDLE hFile = CreateFile(L"example.txt", GENERIC_READ, FILE_SHARE_READ, NULL, OPEN_EXISTING, FILE_ATTRIBUTE_NORMAL, NULL);

    if (hFile == INVALID_HANDLE_VALUE) {
        std::cerr << "Error opening file: "<< GetLastError()<< std::endl;
        return 1;
    }

    // 获取与句柄关联的完整路径名称
    WCHAR buffer[MAX_PATH];
    DWORD dwResult = GetFinalPathNameByHandle(hFile, buffer, MAX_PATH, FILE_NAME_NORMALIZED);

    if (dwResult == 0) {
        std::cerr << "Error getting file path: "<< GetLastError()<< std::endl;
        CloseHandle(hFile);
        return 1;
    }

    std::wcout << L"File path: "<< buffer<< std::endl;

    // 关闭文件句柄
    CloseHandle(hFile);

    return 0;
}