如何解组xml并将其映射到POJO？

// 1. 导入相关的依赖库
import javax.xml.bind.JAXBContext;
import javax.xml.bind.JAXBException;
import javax.xml.bind.Unmarshaller;
import java.io.File;

// 2. 创建POJO类
public class Person {
    private String name;
    private int age;

    // 省略构造函数和getter/setter方法
}

// 3. 创建XML解析器
public class XMLParser {
    public static Person parseXML(String xmlFilePath) throws JAXBException {
        // 创建JAXBContext对象
        JAXBContext jaxbContext = JAXBContext.newInstance(Person.class);

        // 创建Unmarshaller对象
        Unmarshaller unmarshaller = jaxbContext.createUnmarshaller();

        // 解析XML文件并将其映射到POJO对象
        Person person = (Person) unmarshaller.unmarshal(new File(xmlFilePath));

        return person;
    }
}

// 4. 解析XML并访问POJO对象
public class Main {
    public static void main(String[] args) {
        try {
            // 解析XML文件
            Person person = XMLParser.parseXML("person.xml");

            // 访问POJO对象的字段和属性
            System.out.println("Name: " + person.getName());
            System.out.println("Age: " + person.getAge());
        } catch (JAXBException e) {
            e.printStackTrace();
        }
    }
}