如何计算每周队列的不同id计数？

import collections

def count_unique_ids(data):
    id_counts = collections.defaultdict(int)
    for item in data:
        id_counts[item['id']] += 1
    
    sorted_counts = sorted(id_counts.items(), key=lambda x: x[1], reverse=True)
    for id, count in sorted_counts:
        print(f"ID: {id}, Count: {count}")

# 假设data为每周队列的数据，格式为列表，每个元素为字典，包含'id'字段
data = [
    {'id': 'A'},
    {'id': 'B'},
    {'id': 'A'},
    {'id': 'C'},
    {'id': 'B'},
    {'id': 'D'},
    {'id': 'A'},
    {'id': 'B'},
    {'id': 'C'},
]

count_unique_ids(data)

ID: A, Count: 3
ID: B, Count: 3
ID: C, Count: 2
ID: D, Count: 1