如何计算每行2个时间戳的总差值

import datetime

def calculate_total_difference(timestamps):
    total_difference = datetime.timedelta()  # 初始化总差值为0

    for line in timestamps:
        # 提取时间戳
        timestamp1, timestamp2 = line.split(',')

        # 转换为日期时间对象
        datetime1 = datetime.datetime.strptime(timestamp1, '%Y-%m-%d %H:%M:%S')
        datetime2 = datetime.datetime.strptime(timestamp2, '%Y-%m-%d %H:%M:%S')

        # 计算差值
        difference = datetime2 - datetime1

        # 累加差值
        total_difference += difference

    return total_difference

# 示例时间戳数据
timestamps = [
    '2022-01-01 12:00:00,2022-01-01 12:30:00',
    '2022-01-02 09:00:00,2022-01-02 10:00:00',
    '2022-01-03 18:00:00,2022-01-03 19:30:00'
]

# 计算总差值
total_difference = calculate_total_difference(timestamps)

print(f"总差值: {total_difference}")