如何让一个方法等待另一个方法完成？

import threading

def method1():
    print("Method 1")
    
def method2():
    print("Method 2")

# 创建线程
t1 = threading.Thread(target=method1)
t2 = threading.Thread(target=method2)

# 启动线程
t1.start()
t1.join()  # 等待t1线程执行完成
t2.start()

import threading

lock = threading.Lock()

def method1():
    lock.acquire()  # 获取锁
    try:
        print("Method 1")
    finally:
        lock.release()  # 释放锁
    
def method2():
    lock.acquire()  # 获取锁
    try:
        print("Method 2")
    finally:
        lock.release()  # 释放锁

# 创建线程
t1 = threading.Thread(target=method1)
t2 = threading.Thread(target=method2)

# 启动线程
t1.start()
t2.start()