如何让Python返回函数的抽象表达式并获取其中的参数？

import inspect

def get_function_expression(func):
    signature = inspect.signature(func)
    parameters = signature.parameters

    expression = f"{func.__name__}("

    for name, parameter in parameters.items():
        expression += name

        if parameter.default != inspect.Parameter.empty:
            expression += f"={parameter.default}"

        if parameter.annotation != inspect.Parameter.empty:
            expression += f": {parameter.annotation}"

        expression += ", "

    if len(parameters) > 0:
        expression = expression[:-2]  # 去掉最后的逗号和空格

    expression += ")"

    return expression

def example_func(a, b=10, c: str = "hello"):
    pass

expression = get_function_expression(example_func)
print(expression)

example_func(a, b=10, c: str = hello)