如何输出从列表中找到最大频率值的字典？

def find_max_frequency(lst):
    frequency_dict = {}
    max_frequency = 0
    max_frequency_dict = {}

    # 统计每个元素的频率
    for item in lst:
        if item in frequency_dict:
            frequency_dict[item] += 1
        else:
            frequency_dict[item] = 1

    # 找到最大频率值
    for item, frequency in frequency_dict.items():
        if frequency > max_frequency:
            max_frequency = frequency

    # 找到频率值等于最大频率值的元素
    for item, frequency in frequency_dict.items():
        if frequency == max_frequency:
            max_frequency_dict[item] = frequency

    return max_frequency_dict

# 示例用法
lst = [1, 2, 3, 2, 1, 3, 4, 5, 4, 4, 4]
result = find_max_frequency(lst)
print(result)