如何过滤ResourceList中的项目

def filter_resource_list(resource_list, condition):
    filtered_list = []
    for item in resource_list:
        if condition(item):
            filtered_list.append(item)
    return filtered_list

# 示例数据
resource_list = [
    {"name": "file1.txt", "type": "text", "size": 100},
    {"name": "image.jpg", "type": "image", "size": 500},
    {"name": "video.mp4", "type": "video", "size": 1000}
]

# 过滤条件：过滤出类型为图片的项目
filtered_list = filter_resource_list(resource_list, lambda item: item["type"] == "image")

# 打印过滤结果
for item in filtered_list:
    print(item["name"])

# 输出结果：image.jpg