如何退出通过URL方案打开的unity应用程序并返回主应用程序？

Application.OpenURL("myapp://");

// UnityAppController.mm

// 导入UnityAppController头文件
#include "UnityAppController.h"

// 注册URL Scheme Handler
void RegisterURLSchemeHandler()
{
    UnityAppController* appController = (UnityAppController*)[UIApplication sharedApplication].delegate;
    [appController setURLSchemeHandler:^(NSURL* url) {
        // 执行退出操作并返回主应用程序
        [appController quitUnityAndReturnToMainApplication];
    }];
}

// PlayerActivity.java

// 导入PlayerActivity相关的类
import com.unity3d.player.UnityPlayer;
import android.content.Intent;
import android.net.Uri;

// 注册URL Scheme Handler
void registerURLSchemeHandler()
{
    PlayerActivity playerActivity = UnityPlayer.currentActivity;
    playerActivity.registerReceiver(new BroadcastReceiver() {
        @Override
        public void onReceive(Context context, Intent intent) {
            // 获取URL数据
            Uri data = intent.getData();
            // 执行退出操作并返回主应用程序
            UnityPlayer.UnitySendMessage("GameObjectName", "MethodName", "QuitAndReturnToMainApp");
        }
    }, new IntentFilter("android.intent.action.VIEW"));
}