如何递归子节点并输出为json？

import json

def get_json(node):
    if node.is_leaf():
        # 如果节点是叶子节点，直接返回节点的值
        return node.value
    else:
        # 如果节点有子节点，递归调用该函数
        children = []
        for child in node.children:
            child_json = get_json(child)
            children.append(child_json)
        
        # 返回包含子节点数据的JSON对象
        return {
            "name": node.name,
            "children": children
        }

# 示例节点类
class Node:
    def __init__(self, name, value=None):
        self.name = name
        self.value = value
        self.children = []
    
    def add_child(self, child):
        self.children.append(child)
    
    def is_leaf(self):
        return len(self.children) == 0

# 创建示例节点树
root = Node("Root")
node1 = Node("Node 1", "Value 1")
node2 = Node("Node 2", "Value 2")
node3 = Node("Node 3", "Value 3")
node4 = Node("Node 4", "Value 4")
node5 = Node("Node 5", "Value 5")

root.add_child(node1)
root.add_child(node2)
node2.add_child(node3)
node2.add_child(node4)
node4.add_child(node5)

# 递归获取JSON数据
json_data = get_json(root)

# 输出JSON数据
print(json.dumps(json_data, indent=4))

{
    "name": "Root",
    "children": [
        {
            "name": "Node 1",
            "value": "Value 1"
        },
        {
            "name": "Node 2",
            "children": [
                {
                    "name": "Node 3",
                    "value": "Value 3"
                },
                {
                    "name": "Node 4",
                    "children": [
                        {
                            "name": "Node 5",
                            "value": "Value 5"
                        }
                    ]
                }
            ]
        }
    ]
}