如何通过嵌套数组中的键获取交集，然后通过前一个键获取另一个键的所有值

function getIntersectionValues(nestedArray, key1, key2) {
  // 构建存储键值对的字典
  const dict = {};
  nestedArray.forEach(item => {
    if (item.hasOwnProperty(key1)) {
      dict[item[key1]] = item[key2];
    }
  });

  // 获取交集的起始点的值
  const startValue = dict[nestedArray[0][key1]];

  // 获取交集集合中的键
  const intersectKeys = Object.keys(dict).filter(key => {
    return nestedArray.every(item => item.hasOwnProperty(key) && item[key] === startValue);
  });

  // 获取第二个键的所有值
  const result = intersectKeys.map(key => dict[key]);

  return result;
}

// 示例数据
const nestedArray = [
  { category: 'fruit', type: 'apple', value: 'red' },
  { category: 'fruit', type: 'banana', value: 'yellow' },
  { category: 'fruit', type: 'orange', value: 'orange' },
  { category: 'vegetable', type: 'carrot', value: 'orange' },
  { category: 'vegetable', type: 'celery', value: 'green' }
];

// 使用示例
const intersectionValues = getIntersectionValues(nestedArray, 'category', 'value');
console.log(intersectionValues);