如何通过PostGIS数据库在Spring boot中使用PointZ类型

<dependency>
    <groupId>org.postgresql</groupId>
    <artifactId>postgresql</artifactId>
    <version>版本号</version>
</dependency>

<dependency>
    <groupId>org.springframework.boot</groupId>
    <artifactId>spring-boot-starter-data-jpa</artifactId>
</dependency>

spring.datasource.url=jdbc:postgresql://localhost:5432/数据库名
spring.datasource.username=用户名
spring.datasource.password=密码
spring.jpa.database-platform=org.hibernate.spatial.dialect.postgis.PostgisDialect

import com.vividsolutions.jts.geom.Point;

@Entity
@Table(name = "表名")
public class EntityName {
    @Id
    @GeneratedValue(strategy = GenerationType.IDENTITY)
    private Long id;

    @Column(name = "point_column", columnDefinition = "geometry(PointZ,4326)")
    private Point point;

    // 其他字段和方法
}

import org.springframework.data.jpa.repository.JpaRepository;

public interface EntityNameRepository extends JpaRepository<EntityName, Long> {
}

import com.vividsolutions.jts.geom.Point;
import org.springframework.beans.factory.annotation.Autowired;
import org.springframework.stereotype.Service;

@Service
public class EntityNameService {
    @Autowired
    private EntityNameRepository entityNameRepository;

    public void saveEntity(EntityName entity) {
        Point point = new GeometryFactory().createPoint(new Coordinate(x, y, z));
        entity.setPoint(point);
        entityNameRepository.save(entity);
    }

    // 其他业务逻辑方法
}