如何通过python socket从服务器接收多个列表？

import socket
import pickle

# 服务器地址和端口
server_address = ('localhost', 8888)

# 创建socket对象
client_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

# 连接服务器
client_socket.connect(server_address)

# 接收列表的数量
list_count = client_socket.recv(1024).decode()

# 循环接收多个列表
for i in range(int(list_count)):
    # 接收列表的长度
    list_length = client_socket.recv(1024).decode()

    # 接收列表数据
    list_data = client_socket.recv(int(list_length))

    # 反序列化列表
    received_list = pickle.loads(list_data)

    # 处理接收到的列表
    print("Received List:", received_list)

# 关闭socket连接
client_socket.close()

import socket
import pickle

# 服务器地址和端口
server_address = ('localhost', 8888)

# 创建socket对象
server_socket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

# 绑定地址和端口
server_socket.bind(server_address)

# 监听连接
server_socket.listen(1)

# 等待客户端连接
client_socket, client_address = server_socket.accept()

# 多个列表数据
lists = [[1, 2, 3], ['a', 'b', 'c'], [True, False]]

# 发送列表的数量
client_socket.send(str(len(lists)).encode())

# 循环发送多个列表
for lst in lists:
    # 序列化列表
    list_data = pickle.dumps(lst)

    # 发送列表的长度
    client_socket.send(str(len(list_data)).encode())

    # 发送列表数据
    client_socket.send(list_data)

# 关闭socket连接
client_socket.close()
server_socket.close()