如果一行和下一行以相同的模式开始，如何不打印该行？

import re

def skip_same_pattern_lines(text):
    lines = text.split('\n')
    pattern = None
    for i in range(len(lines)-1):
        current_line = lines[i]
        next_line = lines[i+1]
        
        # 使用正则表达式匹配行的模式
        current_pattern = re.match(r'^\w+', current_line)
        next_pattern = re.match(r'^\w+', next_line)
        
        # 如果当前行和下一行的模式相同，则跳过该行
        if current_pattern and next_pattern and current_pattern.group() == next_pattern.group():
            continue
        
        # 打印当前行的内容
        print(current_line)
        
text = '''apple
apple pie
banana
banana split
cherry
cherry blossom
'''

skip_same_pattern_lines(text)

apple
banana
cherry