如果不在shell中显示，如何计算包含特定八进制代码的文件的数量

import os

def count_files_with_octal_code(directory, octal_code):
    count = 0

    for root, dirs, files in os.walk(directory):
        for file in files:
            file_path = os.path.join(root, file)
            with open(file_path, 'r') as f:
                for line in f:
                    if octal_code in line:
                        count += 1

    return count

directory = '/path/to/directory'  # 替换为要搜索的目录路径
octal_code = '\033'  # 替换为要搜索的特定八进制代码

file_count = count_files_with_octal_code(directory, octal_code)
print("包含特定八进制代码的文件数量：", file_count)