如果列表中包含给定元素，则从列表中删除子列表

def remove_sublists_with_element(lst, element):
    i = 0
    while i < len(lst):
        if element in lst[i]:
            lst.pop(i)
        else:
            i += 1

# 示例用法
my_list = [[1, 2, 3], [4, 5, 6], [7, 8, 9]]
remove_sublists_with_element(my_list, 5)
print(my_list)  # 输出: [[1, 2, 3], [7, 8, 9]]