如果list包含另一个子列表的任何字符串，则在pandas中创建新列

def contains_sublist(lst, sublist):
    for item in sublist:
        if item in lst:
            return True
    return False

import pandas as pd

# 创建一个示例DataFrame
data = {'list_col': [['apple', 'banana', 'orange'], ['grape', 'melon'], ['pear', 'kiwi']]}
df = pd.DataFrame(data)

# 定义子列表
sublist = ['banana', 'kiwi']

# 使用apply函数和lambda表达式创建新列
df['contains_sublist'] = df['list_col'].apply(lambda x: contains_sublist(x, sublist))

print(df)

             list_col  contains_sublist
0  [apple, banana, orange]              True
1         [grape, melon]             False
2           [pear, kiwi]              True