字符串C中的循环求和数字

def cyclic_sum(s):
    total_sum = 0
    n = len(s)
    for i in range(n):
        current_sum = 0
        for j in range(i, n):
            current_sum += int(s[j])
            total_sum += current_sum
    return total_sum

# 示例
s = "123"
print(cyclic_sum(s))  # 输出：16 (1 + 2 + 3 + 12 + 23 + 123)

def cyclic_sum_with_check(s):
    total_sum = 0
    n = len(s)
    for i in range(n):
        current_sum = 0
        for j in range(i, n):
            if s[j].isdigit():
                current_sum += int(s[j])
                total_sum += current_sum
            else:
                current_sum = 0  # 重置当前和
    return total_sum

# 示例
s = "a1b2c3"
print(cyclic_sum_with_check(s))  # 输出：6 (1 + 2 + 3)