安卓ListView onItemClick在确切位置显示弹出窗口

listView.setOnItemClickListener(new AdapterView.OnItemClickListener() {
    @Override
    public void onItemClick(AdapterView<?> parent, View view, int position, long id) {
        // 获取点击项的位置
        int[] location = new int[2];
        view.getLocationOnScreen(location);
        int x = location[0];
        int y = location[1];

        // 创建PopupWindow对象
        PopupWindow popupWindow = new PopupWindow(context);
        popupWindow.setWidth(ViewGroup.LayoutParams.WRAP_CONTENT);
        popupWindow.setHeight(ViewGroup.LayoutParams.WRAP_CONTENT);
        popupWindow.setContentView(contentView); // 设置弹出窗口的内容视图

        // 设置PopupWindow的显示位置
        popupWindow.showAtLocation(view, Gravity.NO_GRAVITY, x, y + view.getHeight());

        // 设置PopupWindow的动画效果
        popupWindow.setAnimationStyle(R.style.PopupAnimation);

        // 显示PopupWindow
        popupWindow.show();
    }
});