对于对的列表，我如何引用第二个相同的元素，然后对第一个元素进行排序？

def sort_second_duplicate(lst):
    count = 0
    second_duplicate = None
    
    for elem in lst:
        if elem == lst[0]:
            count += 1
            if count == 2:
                second_duplicate = elem
    
    if second_duplicate is not None:
        lst.sort()
    
    return second_duplicate, lst

# 示例用法
my_list = [3, 5, 2, 1, 3, 4, 5, 6, 3, 2]
second_duplicate, sorted_list = sort_second_duplicate(my_list)

print("第二个相同元素:", second_duplicate)
print("排序后的列表:", sorted_list)

第二个相同元素: 3
排序后的列表: [1, 2, 2, 3, 3, 3, 4, 5, 5, 6]