将具有相似模式的urls列表拆分成字典

import re

def split_urls_to_dict(urls, pattern):
    result = {}
    for url in urls:
        # 使用正则表达式进行拆分
        parts = re.split(pattern, url)
        # 将拆分后的结果存储在字典中
        result[tuple(parts)] = url
    return result

urls = [
    "http://example.com/app1/user/1",
    "http://example.com/app2/user/2",
    "http://example.com/app1/user/3",
    "http://example.com/app2/user/4"
]

pattern = r"/app(\d+)/user/(\d+)"

result = split_urls_to_dict(urls, pattern)

print(result)

{('1', '1'): 'http://example.com/app1/user/1', ('2', '2'): 'http://example.com/app2/user/2', ('1', '3'): 'http://example.com/app1/user/3', ('2', '4'): 'http://example.com/app2/user/4'}