将列表拆分为偶数大小的重叠块n-max

def split_list_into_even_overlapping_chunks(lst, n_max):
    if n_max % 2 != 0:
        raise ValueError("n_max must be an even number.")
    
    chunk_size = n_max // 2
    chunks = []
    for i in range(0, len(lst) - chunk_size + 1, chunk_size // 2):
        chunks.append(lst[i:i + n_max])
    
    return chunks

# 示例
lst = [1, 2, 3, 4, 5, 6, 7, 8, 9]
n_max = 6
result = split_list_into_even_overlapping_chunks(lst, n_max)
print(result)

[[1, 2, 3, 4, 5, 6], [4, 5, 6, 7, 8, 9]]