将复杂的curl命令转换为python3

import requests

session = requests.Session()

headers = {
    'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3',
    'Accept': 'text/html,application/xhtml+xml,application/xml;q=0.9,image/webp,image/apng,*/*;q=0.8',
    'Accept-Language': 'en-US,en;q=0.9',
    'Referer': 'https://www.example.com'
}

response = session.get(url, headers=headers, params=params)

data = {
    'username': 'example',
    'password': 'password123'
}
response = session.post(url, headers=headers, data=data)

print(response.status_code)  # 打印响应状态码
print(response.text)  # 打印响应内容