将多个列表变量转换为所需排列的矩阵

# 假设有三个列表变量A、B、C
A = [1, 2, 3]
B = [4, 5]
C = [6, 7, 8, 9]

# 创建一个空的矩阵
matrix = []

# 遍历列表变量，将元素添加到矩阵中
for i in range(max(len(A), len(B), len(C))):
    row = []
    if i < len(A):
        row.append(A[i])
    else:
        row.append(None)
    if i < len(B):
        row.append(B[i])
    else:
        row.append(None)
    if i < len(C):
        row.append(C[i])
    else:
        row.append(None)
    matrix.append(row)

# 打印转换后的矩阵
for row in matrix:
    print(row)

[1, 4, 6]
[2, 5, 7]
[3, None, 8]
[None, None, 9]