将多级列表中的"0“和"1”字符串转换为整数

def convert_to_integer(lst):
    if not lst:
        return 0
    
    first = lst[0]
    if isinstance(first, str) and first in ["0", "1"]:
        return int(first)
    elif isinstance(first, list):
        return convert_to_integer(first) * 2 + convert_to_integer(lst[1:])
    else:
        return convert_to_integer(lst[1:])

# 示例用法
lst = [[["1", "0"], "1"], ["0", ["1", "0"]]]
result = convert_to_integer(lst)
print(result)  # 输出：10