将多行Json用户输入格式化为单行Json字符串，以便在Java console应用程序中传递给JsonParser

import com.fasterxml.jackson.core.JsonProcessingException;
import com.fasterxml.jackson.databind.JsonNode;
import com.fasterxml.jackson.databind.ObjectMapper;

public class JsonFormatter {
    public static void main(String[] args) {
        // 多行Json用户输入
        String multiLineJson = "{\n" +
                "  \"name\": \"John\",\n" +
                "  \"age\": 30,\n" +
                "  \"city\": \"New York\"\n" +
                "}";

        // 去除换行符和空格，合并为单行Json字符串
        String singleLineJson = multiLineJson.replaceAll("\\s+", "");

        // 使用Jackson解析Json字符串
        ObjectMapper objectMapper = new ObjectMapper();
        try {
            JsonNode jsonNode = objectMapper.readTree(singleLineJson);

            // 将Json对象转换为单行Json字符串
            String formattedJson = objectMapper.writeValueAsString(jsonNode);
            System.out.println(formattedJson);
        } catch (JsonProcessingException e) {
            e.printStackTrace();
        }
    }
}