将嵌套列表字符串转换为列表

def convert_nested_list_string(nested_list_string):
    nested_list_string = nested_list_string.strip("[]")  # 去除外层方括号
    result = []
    temp = ""
    count = 0

    for char in nested_list_string:
        if char == "[":
            count += 1
        elif char == "]":
            count -= 1

        if char == "," and count == 0:
            result.append(temp.strip())
            temp = ""
        else:
            temp += char

    if temp:
        result.append(temp.strip())

    for i in range(len(result)):
        if "[" in result[i]:
            result[i] = convert_nested_list_string(result[i])  # 递归转换嵌套列表

    return result

# 示例用法
nested_list_string = "[1, 2, [3, 4], [5, [6, 7]]]"
nested_list = convert_nested_list_string(nested_list_string)
print(nested_list)