将数据从C# WindowsForm发布到Php并更新输入值。

using System;
using System.Net;
using System.IO;

public class Program
{
    public static void Main()
    {
        // 准备要发送的数据
        string data = "inputValue=123";

        // 创建一个Web请求对象
        WebRequest request = WebRequest.Create("http://your-php-api-url");

        // 设置请求方法为POST
        request.Method = "POST";

        // 将数据转换为字节数组
        byte[] byteArray = System.Text.Encoding.UTF8.GetBytes(data);

        // 设置请求的内容类型
        request.ContentType = "application/x-www-form-urlencoded";

        // 设置请求的内容长度
        request.ContentLength = byteArray.Length;

        // 获取请求的输出流
        Stream dataStream = request.GetRequestStream();

        // 将数据写入请求的输出流
        dataStream.Write(byteArray, 0, byteArray.Length);

        // 关闭请求的输出流
        dataStream.Close();

        // 发送请求并获取响应
        WebResponse response = request.GetResponse();

        // 获取响应的状态码
        HttpStatusCode statusCode = ((HttpWebResponse)response).StatusCode;

        // 关闭响应
        response.Close();

        // 根据响应的状态码判断是否成功
        if (statusCode == HttpStatusCode.OK)
        {
            Console.WriteLine("数据发布成功！");
        }
        else
        {
            Console.WriteLine("数据发布失败！");
        }
    }
}

<?php
// 获取来自C# WindowsForm的数据
$inputValue = $_POST['inputValue'];

// 连接数据库
$servername = "your-servername";
$username = "your-username";
$password = "your-password";
$dbname = "your-dbname";

$conn = new mysqli($servername, $username, $password, $dbname);

// 检查数据库连接是否成功
if ($conn->connect_error) {
    die("数据库连接失败: " . $conn->connect_error);
}

// 更新输入值
$sql = "UPDATE your-table SET inputValue = '$inputValue' WHERE id = 1";

if ($conn->query($sql) === TRUE) {
    echo "输入值更新成功！";
} else {
    echo "输入值更新失败: " . $conn->error;
}

// 关闭数据库连接
$conn->close();
?>