将用户输入的数字转换为单词

def number_to_words(num):
    # 定义数字和对应单词的映射关系
    words_map = {
        0: "zero",
        1: "one",
        2: "two",
        3: "three",
        4: "four",
        5: "five",
        6: "six",
        7: "seven",
        8: "eight",
        9: "nine",
        10: "ten",
        11: "eleven",
        12: "twelve",
        13: "thirteen",
        14: "fourteen",
        15: "fifteen",
        16: "sixteen",
        17: "seventeen",
        18: "eighteen",
        19: "nineteen",
        20: "twenty",
        30: "thirty",
        40: "forty",
        50: "fifty",
        60: "sixty",
        70: "seventy",
        80: "eighty",
        90: "ninety",
        100: "hundred",
        1000: "thousand",
        1000000: "million",
        1000000000: "billion"
    }

    # 处理特殊情况
    if num == 0:
        return words_map[num]

    # 定义函数将三位数转换为单词
    def convert_three_digits(num):
        words = []
        if num >= 100:
            words.append(words_map[num // 100])
            words.append(words_map[100])
            num %= 100
        if num >= 20:
            words.append(words_map[num // 10 * 10])
            num %= 10
        if num > 0:
            words.append(words_map[num])
        return " ".join(words)

    # 将数字按照三位一组进行分组
    groups = []
    while num > 0:
        groups.append(num % 1000)
        num //= 1000

    # 将每个三位数转换为单词，并加上对应的单位
    result = []
    for i in range(len(groups)):
        if groups[i] > 0:
            result.append(convert_three_digits(groups[i]))
            if i < len(groups) - 1:
                result.append(words_map[1000 ** (i + 1)])

    # 将单词列表反转并连接起来
    return " ".join(result[::-1])