左侧去掉字符串中第二个数字之前的所有内容

def remove_before_second_number(string):
    first_number_index = -1
    second_number_index = -1
    count = 0

    for i in range(len(string)):
        if string[i].isdigit():
            count += 1
            if count == 1:
                first_number_index = i
            elif count == 2:
                second_number_index = i
                break

    if second_number_index != -1:
        return string[second_number_index:]
    else:
        return ""

# 示例用法
string = "abc123def456ghi789"
result = remove_before_second_number(string)
print(result)  # 输出：456ghi789