当调用SetState()时，如何避免UniqueKey闪烁的颤动FutureBuilder？

int _counter = 0;

@override
Widget build(BuildContext context) {
  return Scaffold(
    appBar: AppBar(
      title: Text('Example'),
    ),
    body: FutureBuilder(
      key: ValueKey(_counter), // 使用ValueKey
      future: fetchData(),
      builder: (BuildContext context, AsyncSnapshot snapshot) {
        if (snapshot.connectionState == ConnectionState.waiting) {
          return CircularProgressIndicator();
        } else if (snapshot.hasError) {
          return Text('Error: ${snapshot.error}');
        } else {
          return Text('Data: ${snapshot.data}');
        }
      },
    ),
    floatingActionButton: FloatingActionButton(
      onPressed: () {
        setState(() {
          _counter++; // 每次调用SetState()时更新_counter的值
        });
      },
      child: Icon(Icons.add),
    ),
  );
}

Future<String> fetchData() async {
  // 模拟异步获取数据
  await Future.delayed(Duration(seconds: 2));
  return 'Data';
}