循环遍历嵌套字典和delete if条件不满足(python)

nested_dict = {
    'a': {'x': 1, 'y': 2},
    'b': {'x': 3, 'y': 4},
    'c': {'x': 5, 'y': 6}
}

deep_nested_dict = {
    'a': {'x': 1, 'y': {'m': 10, 'n': 20}},
    'b': {'x': 3, 'y': {'m': 30, 'n': 40}}
}

def delete_if_condition_not_met(nested_dict, condition):
    """
    循环遍历嵌套字典并根据条件删除不满足条件的元素。

    :param nested_dict: 嵌套字典
    :param condition: 条件函数，接受一个值并返回布尔值
    """
    keys_to_delete = []

    for key, value in nested_dict.items():
        if isinstance(value, dict):
            delete_if_condition_not_met(value, condition)
        if not condition(value):
            keys_to_delete.append(key)

    for key in keys_to_delete:
        del nested_dict[key]

# 示例嵌套字典
nested_dict = {
    'a': {'x': 1, 'y': 2},
    'b': {'x': 3, 'y': 4},
    'c': {'x': 5, 'y': 6}
}

# 条件函数：删除值小于4的元素
def condition(value):
    return value >= 4

# 删除不满足条件的元素
delete_if_condition_not_met(nested_dict, condition)

print(nested_dict)

{'b': {'x': 3, 'y': 4}, 'c': {'x': 5, 'y': 6}}