#include <iostream>
{ int* ptr = const_cast<int*>(&kiNum); cout<<"kiNum: "<<kiNum; // The value still prints 100 on the console??}
kiNum = 100
在上面的代码片段中,
我纠结于这个问题的起因。如果我以我的帐户登录,下面的代码不会显示user: 100000920350966,但如果我注销并重新登录到我妻子的帐户,我现在可以看到该用户的个人资料图片。一个有效的例子是:function randomUser() {
$query = mysql_query("SELECT the_facebook_id FROM users WHERE the_facebook_id != '$facebook_id' ORDER BY RAND() LIMIT 0,