我如何删除我输入的最后一个元素，如果我想要删除所有元素？

var array = [1, 2, 3, 4, 5];
var lastElement = array.pop(); // 删除并返回最后一个元素
console.log(lastElement); // 输出：5
console.log(array); // 输出：[1, 2, 3, 4]

class Node:
    def __init__(self, data=None):
        self.data = data
        self.next = None

class LinkedList:
    def __init__(self):
        self.head = None

    def delete_last_element(self):
        if self.head is None:
            return
        if self.head.next is None:
            self.head = None
            return
        second_last = self.head
        while second_last.next.next:
            second_last = second_last.next
        second_last.next = None

# 创建链表
linked_list = LinkedList()
linked_list.head = Node(1)
second = Node(2)
third = Node(3)
linked_list.head.next = second
second.next = third

# 删除最后一个元素
linked_list.delete_last_element()

# 输出链表
current = linked_list.head
while current:
    print(current.data)
    current = current.next

var array = [1, 2, 3, 4, 5];
array.splice(0, array.length); // 从索引0开始删除所有元素
console.log(array); // 输出：[]

class Node:
    def __init__(self, data=None):
        self.data = data
        self.next = None

class LinkedList:
    def __init__(self):
        self.head = None

    def delete_all_elements(self):
        current = self.head
        while current:
            next_node = current.next
            del current
            current = next_node
        self.head = None

# 创建链表
linked_list = LinkedList()
linked_list.head = Node(1)
second = Node(2)
third = Node(3)
linked_list.head.next = second
second.next = third

# 删除所有元素
linked_list.delete_all_elements()

# 输出链表
current = linked_list.head
while current:
    print(current.data)
    current = current.next