我如何在sequelize中做到这一点？

const { Sequelize } = require('sequelize');

const sequelize = new Sequelize('database', 'username', 'password', {
  host: 'localhost',
  dialect: 'mysql',
  port: 3306,
});

const { DataTypes } = require('sequelize');

const User = sequelize.define('User', {
  id: {
    type: DataTypes.INTEGER,
    primaryKey: true,
    autoIncrement: true,
  },
  name: {
    type: DataTypes.STRING,
    allowNull: false,
  },
  email: {
    type: DataTypes.STRING,
    allowNull: false,
    unique: true,
    validate: {
      isEmail: true,
    },
  },
});

const users = await User.findAll(); // 查询所有用户
const user = await User.findOne({ where: { id: 1 } }); // 根据条件查询单个用户

const user = await User.create({ name: 'John Doe', email: 'john@example.com' }); // 创建用户

await User.update({ name: 'Jane Doe' }, { where: { id: 1 } }); // 更新用户信息

await User.destroy({ where: { id: 1 } }); // 删除用户

const Post = sequelize.define('Post', {
  title: DataTypes.STRING,
  content: DataTypes.TEXT,
});

User.hasMany(Post, { as: 'posts' }); // 一个用户拥有多篇文章
Post.belongsTo(User, { as: 'author' }); // 一篇文章属于一个用户

npx sequelize-cli migration:generate --name create-users

npx sequelize-cli db:migrate

npx sequelize-cli seed:generate --name demo-users

npx sequelize-cli db:seed:all