我有一个15到30个坐标的列表。给定任何X，Y坐标，从前端找到列表中最接近的坐标的方法是什么？

function findClosestCoordinate(coordinates, targetX, targetY) {
  let closestCoordinate = null;
  let minDistance = Infinity;

  for (let i = 0; i < coordinates.length; i++) {
    const coordinate = coordinates[i];
    const distance = Math.sqrt(Math.pow(coordinate.x - targetX, 2) + Math.pow(coordinate.y - targetY, 2));

    if (distance < minDistance) {
      minDistance = distance;
      closestCoordinate = coordinate;
    }
  }

  return closestCoordinate;
}

// 示例用法
const coordinates = [
  { x: 1, y: 2 },
  { x: 3, y: 4 },
  { x: 5, y: 6 },
  // ... 其他坐标
];

const targetX = 7;
const targetY = 8;

const closestCoordinate = findClosestCoordinate(coordinates, targetX, targetY);
console.log(closestCoordinate); // 输出最接近的坐标对象