打印出从列表的Y元素中选择的X个不同对象的所有组合

def combinations(lst, x):
    result = []
    if x == 0 or len(lst) < x:
        return result
    if x == 1:
        for item in lst:
            result.append([item])
    else:
        for i in range(len(lst)-x+1):
            for comb in combinations(lst[i+1:], x-1):
                result.append([lst[i]] + comb)
    return result

# 示例调用
lst = [1, 2, 3, 4, 5]
x = 3
print(combinations(lst, x))