是否有可能从zipinputstream获得zipentry的输入流？

import java.io.BufferedInputStream;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.util.zip.ZipEntry;
import java.util.zip.ZipInputStream;

public class ZipEntryInputStream {
    public static void main(String[] args) {
        try {
            InputStream inputStream = new FileInputStream("path/to/zipfile.zip");
            BufferedInputStream bufferedInputStream = new BufferedInputStream(inputStream);
            ZipInputStream zipInputStream = new ZipInputStream(bufferedInputStream);

            ZipEntry zipEntry = zipInputStream.getNextEntry();
            while (zipEntry != null) {
                if (zipEntry.getName().equals("desired_file_name")) {
                    // 获取ZipEntry的输入流
                    InputStream zipEntryInputStream = new BufferedInputStream(zipInputStream);
                    // 处理输入流
                    // ...
                }
                zipEntry = zipInputStream.getNextEntry();
            }
            zipInputStream.close();
        } catch (IOException e) {
            e.printStackTrace();
        }
    }
}