有办法从返回的create()对象中排除属性吗？

from sqlalchemy import create_engine, Column, Integer, String
from sqlalchemy.ext.declarative import declarative_base
from sqlalchemy.orm import sessionmaker

Base = declarative_base()

class User(Base):
    __tablename__ = 'users'
    id = Column(Integer, primary_key=True)
    name = Column(String)
    email = Column(String)

engine = create_engine('sqlite:///:memory:')
Base.metadata.create_all(engine)
Session = sessionmaker(bind=engine)
session = Session()

# 添加一些示例数据
session.add_all([
    User(name='Alice', email='alice@example.com'),
    User(name='Bob', email='bob@example.com')
])
session.commit()

# 选择性加载，排除email字段
users = session.query(User.id, User.name).all()
for user in users:
    print(user.id, user.name)

from sqlalchemy.orm import class_mapper

def exclude_fields(obj, fields_to_exclude):
    return {k: v for k, v in obj.__dict__.items() if k not in fields_to_exclude}

user = session.query(User).first()
excluded_user = exclude_fields(user, ['email'])
print(excluded_user)

from sqlalchemy.ext.declarative import declared_attr

class BaseModel(Base):
    __abstract__ = True

    @declared_attr
    def __mapper_args__(cls):
        return {'exclude_properties': ['email']}

class User(BaseModel):
    __tablename__ = 'users'
    id = Column(Integer, primary_key=True)
    name = Column(String)
    email = Column(String)

# 查询时自动排除email字段
users = session.query(User).all()
for user in users:
    print(user.id, user.name)