有没有办法创建一个不污染其实例的属性命名空间的Python类方法？

def namespace_decorator(cls):
    def wrap(*args, **kwargs):
        instance = cls(*args, **kwargs)
        return instance

    setattr(wrap, 'namespace', {})  # 创建一个新的命名空间
    return wrap


@namespace_decorator
class MyClass:
    def __init__(self, name):
        self.name = name

    def add_property(self, key, value):
        self.__class__.namespace[key] = value

    def get_property(self, key):
        return self.__class__.namespace.get(key)


my_obj = MyClass('example')
my_obj.add_property('key1', 'value1')
print(my_obj.get_property('key1'))  # 输出: value1

class NamespaceMeta(type):
    def __init__(cls, name, bases, attrs):
        cls.namespace = {}  # 创建一个新的命名空间
        super().__init__(name, bases, attrs)


class MyClass(metaclass=NamespaceMeta):
    def __init__(self, name):
        self.name = name

    def add_property(self, key, value):
        self.__class__.namespace[key] = value

    def get_property(self, key):
        return self.__class__.namespace.get(key)


my_obj = MyClass('example')
my_obj.add_property('key1', 'value1')
print(my_obj.get_property('key1'))  # 输出: value1