有没有办法存储多种类型的结构成员指针？

#include <iostream>
#include <variant>

struct Foo {
    int x;
};

struct Bar {
    double y;
};

int main() {
    std::variant<Foo*, Bar*> v;

    Foo foo = {42};
    Bar bar = {3.14};

    v = &foo; // 存储Foo*类型的指针
    std::cout << "Foo: " << std::get<Foo*>(v)->x << std::endl;

    v = &bar; // 存储Bar*类型的指针
    std::cout << "Bar: " << std::get<Bar*>(v)->y << std::endl;

    return 0;
}

#include <iostream>
#include <any>

struct Foo {
    int x;
};

struct Bar {
    double y;
};

int main() {
    std::any a;

    Foo foo = {42};
    Bar bar = {3.14};

    a = &foo; // 存储Foo*类型的指针
    std::cout << "Foo: " << std::any_cast<Foo*>(&a)->x << std::endl;

    a = &bar; // 存储Bar*类型的指针
    std::cout << "Bar: " << std::any_cast<Bar*>(&a)->y << std::endl;

    return 0;
}