查找数字中的两位数(非/连续)

def find_two_digit_numbers(number):
    number_str = str(number)
    two_digit_numbers = []
    
    for i in range(len(number_str) - 1):
        current_digit = int(number_str[i])
        next_digit = int(number_str[i+1])
        
        if current_digit >= 10 and current_digit <= 99 and next_digit >= 10 and next_digit <= 99 and abs(current_digit - next_digit) != 1:
            two_digit_numbers.append(current_digit * 10 + next_digit)
    
    return two_digit_numbers

# 示例用法
number = 123456789
result = find_two_digit_numbers(number)
print(result)