检测二维数组中具有公共属性的连续对象

def find_continuous_objects(arr):
    rows = len(arr)
    cols = len(arr[0])
    visited = [[False] * cols for _ in range(rows)]
    result = []

    def dfs(row, col, obj):
        if row < 0 or row >= rows or col < 0 or col >= cols:
            return
        if visited[row][col]:
            return
        if arr[row][col] != obj:
            return

        visited[row][col] = True
        result.append((row, col))

        dfs(row - 1, col, obj)  # 上
        dfs(row + 1, col, obj)  # 下
        dfs(row, col - 1, obj)  # 左
        dfs(row, col + 1, obj)  # 右

    for i in range(rows):
        for j in range(cols):
            if not visited[i][j]:
                obj = arr[i][j]
                dfs(i, j, obj)
                if len(result) > 1:
                    print("连续对象:", result)
                result = []

# 示例二维数组
array = [
    [1, 1, 2, 3],
    [1, 1, 2, 4],
    [5, 5, 6, 7],
    [8, 8, 9, 9]
]

find_continuous_objects(array)