活动记录-如何根据日期时间的差异进行排序(即，排序方式最接近给定的日期时间)？

// 活动记录数组
const activityRecords = [
  { id: 1, datetime: "2022-01-01T10:00:00" },
  { id: 2, datetime: "2022-01-02T08:30:00" },
  { id: 3, datetime: "2022-01-03T15:45:00" },
  { id: 4, datetime: "2022-01-04T12:15:00" },
];

// 给定的日期时间
const givenDatetime = "2022-01-02T12:00:00";

// 计算差异值并排序
activityRecords.sort((a, b) => {
  const diffA = Math.abs(new Date(a.datetime) - new Date(givenDatetime));
  const diffB = Math.abs(new Date(b.datetime) - new Date(givenDatetime));
  return diffA - diffB;
});

// 输出排序后的活动记录
activityRecords.forEach((record) => {
  console.log(record);
});