,可以通过以下步骤实现:
unordered_table = {"key1": "value1", "key2": "value2", "key3": "value3", "key4": "value4"}
dictionary = {}
for key, value in unordered_table.items():
if key in dictionary:
dictionary[key].append(value)
else:
dictionary[key] = [value]
print(dictionary)
{
"key1": ["value1"],
"key2": ["value2"],
"key3": ["value3"],
"key4": ["value4"]
}
请注意,以上仅为示例答案,实际上云计算领域的专家需要深入了解各个领域的技术和产品,并根据具体情况选择适合的解决方案。
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