用两个数组c++重载运算符+

Array operator+(const Array& arr1, const Array& arr2);

#include <iostream>

class Array {
private:
    int* data; // 数组成员变量
    int size; // 数组大小

public:
    // 构造函数
    Array(int* arr, int n) {
        size = n;
        data = new int[size];
        for (int i = 0; i < size; i++) {
            data[i] = arr[i];
        }
    }

    // 析构函数
    ~Array() {
        delete[] data;
    }

    // 重载运算符+
    friend Array operator+(const Array& arr1, const Array& arr2) {
        if (arr1.size != arr2.size) {
            throw std::invalid_argument("数组大小不一致");
        }

        int* result = new int[arr1.size];
        for (int i = 0; i < arr1.size; i++) {
            result[i] = arr1.data[i] + arr2.data[i];
        }

        Array sum(result, arr1.size);
        delete[] result;

        return sum;
    }

    // 获取数组大小
    int getSize() const {
        return size;
    }

    // 获取数组元素
    int getElement(int index) const {
        if (index < 0 || index >= size) {
            throw std::out_of_range("数组下标越界");
        }

        return data[index];
    }
};

int main() {
    int arr1[] = {1, 2, 3};
    int arr2[] = {4, 5, 6};

    Array a(arr1, 3);
    Array b(arr2, 3);

    Array c = a + b;

    for (int i = 0; i < c.getSize(); i++) {
        std::cout << c.getElement(i) << " ";
    }
    std::cout << std::endl;

    return 0;
}