用于将一个星期六的总销售额与今年其余星期六的平均值进行比较的查询

import datetime
import pandas as pd

# 假设销售数据存储在一个名为sales的数据库表中，包含日期和销售额两个字段

# 获取当前日期
current_date = datetime.date.today()

# 获取今年的第一个星期六的日期
first_saturday = current_date - datetime.timedelta(days=current_date.weekday()) + datetime.timedelta(days=5-current_date.weekday())

# 计算今年其余星期六的平均值
total_sales = 0
num_saturdays = 0

# 查询数据库获取销售数据
# 这里假设使用MySQL数据库，并且已经连接到数据库
query = "SELECT SUM(sales) FROM sales WHERE DATEPART(weekday, date) = 7 AND date >= '{}'".format(first_saturday)
result = cursor.execute(query)
total_sales = result.fetchone()[0]

query = "SELECT COUNT(*) FROM sales WHERE DATEPART(weekday, date) = 7 AND date >= '{}'".format(first_saturday)
result = cursor.execute(query)
num_saturdays = result.fetchone()[0]

average_sales = total_sales / num_saturdays

# 查询今年的星期六销售额
query = "SELECT SUM(sales) FROM sales WHERE DATEPART(weekday, date) = 7 AND YEAR(date) = YEAR(CURRENT_DATE)"
result = cursor.execute(query)
current_sales = result.fetchone()[0]

# 比较销售额
if current_sales > average_sales:
    print("本周销售额高于今年其余星期六的平均值")
else:
    print("本周销售额低于今年其余星期六的平均值")