用awk计算滑动窗的中位数

awk -v window_size=5 '
BEGIN {
    # 初始化滑动窗口数组
    for (i = 1; i <= window_size; i++) {
        window[i] = 0
    }
    count = 0
}

{
    # 将当前数据添加到滑动窗口数组中
    index = (count % window_size) + 1
    window[index] = $1
    count++

    # 当滑动窗口数组已满时，开始计算中位数
    if (count >= window_size) {
        # 对滑动窗口数组进行排序
        for (i = 1; i <= window_size; i++) {
            for (j = i + 1; j <= window_size; j++) {
                if (window[i] > window[j]) {
                    temp = window[i]
                    window[i] = window[j]
                    window[j] = temp
                }
            }
        }

        # 计算中位数
        median = (window[int(window_size/2)] + window[int(window_size/2) + 1]) / 2

        # 输出中位数
        print "滑动窗口的中位数为：" median
    }
}
'